WebAug 16, 2024 · The plot presented in Fig. 7 indicates that the bubble with the smaller volume (V 0 = 0.0017 µL) has enlarged almost 70-fold, i.e., almost five times more than has the bubble with a close size in 50% ethanol solution. The bubble with a larger size (1 mm) has grown by nearly three times. WebAug 30, 2024 · 2.4K views 2 years ago The volume of an air bubble becomes three times as it rises from the bottom of a lake to its surface. Assuming atmospheric pressure to be 75 cm of Hg and the...
The volume of an air bubble becomes three times as it …
WebOriginally Answered: The volume of an air bubble is doubled as it rises from the bottom of lake to its surface. The atmospheric pressure is 75 cm of mercury. The ratio of density of mercury to that of lake water is 40:3 . What is the depth of the lake in metres? This problem needs two concepts : (1) mass conservation and (2) ideal gas law. WebArun. 25757 Points. 4 years ago. The ratio of the volume of the air bubble at the top to the bottom, V'/V = 6, V' = 6V. The ratio of the density of the mercury to that of the lake water, p'/p = 10/3. => p' = (10/3) p. Now, the pressure exerted at the surface is equal to 75cm of mercury, so the depth = 0.75m. The pressure exerted at the bottom ... great superhero names
Solved 12 A bubble of air of volume 5.0 mm.is under water. - Chegg
WebThe volume of an air bubble becomes three times as it rises from the bottom of a lake to its surface. Assuming atmospheric pressure to be 75 cm of Hg and the density of water to be 1/10 of the density of mercury, the depth of the lake. WebSolution Verified by Toppr Correct option is A) let the height be h pressure at the bottom = h + 76 (atmospheric pressure) now as it reaches at the top, pressure = 76 (only atmospheric pressure now) at constant temperature we can apply Boyle's law here P 1 = h + 76 P 2 = 76 V 2= 23V 1 so by Boyle's law, we get P 1V 1=P 2V 2 WebMar 27, 2024 · Here the radius of the air bubble at the bottom is ${r_1}$ and the radius of the air bubble at the surface is ${r_2}$. Now we have to apply the formula of ${P_1}{V_1} = {P_2}{V_2}$. Now we have to put the values mentioned in the question in the above equation. So this becomes: $ great superfoods